Optimal. Leaf size=384 \[ -\frac{3 \text{PolyLog}\left (3,1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{3 \text{PolyLog}\left (4,1-\frac{2}{1-a x}\right )}{a^3 c}-\frac{3 \text{PolyLog}\left (5,1-\frac{2}{1-a x}\right )}{2 a^3 c}+\frac{2 \tanh ^{-1}(a x)^3 \text{PolyLog}\left (2,1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{6 \tanh ^{-1}(a x)^2 \text{PolyLog}\left (2,1-\frac{2}{1-a x}\right )}{a^3 c}-\frac{3 \tanh ^{-1}(a x)^2 \text{PolyLog}\left (3,1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{6 \tanh ^{-1}(a x) \text{PolyLog}\left (2,1-\frac{2}{1-a x}\right )}{a^3 c}-\frac{6 \tanh ^{-1}(a x) \text{PolyLog}\left (3,1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{3 \tanh ^{-1}(a x) \text{PolyLog}\left (4,1-\frac{2}{1-a x}\right )}{a^3 c}-\frac{x \tanh ^{-1}(a x)^4}{a^2 c}-\frac{\tanh ^{-1}(a x)^4}{2 a^3 c}-\frac{2 x \tanh ^{-1}(a x)^3}{a^2 c}-\frac{2 \tanh ^{-1}(a x)^3}{a^3 c}+\frac{\log \left (\frac{2}{1-a x}\right ) \tanh ^{-1}(a x)^4}{a^3 c}+\frac{4 \log \left (\frac{2}{1-a x}\right ) \tanh ^{-1}(a x)^3}{a^3 c}+\frac{6 \log \left (\frac{2}{1-a x}\right ) \tanh ^{-1}(a x)^2}{a^3 c}-\frac{x^2 \tanh ^{-1}(a x)^4}{2 a c} \]
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Rubi [A] time = 0.862002, antiderivative size = 384, normalized size of antiderivative = 1., number of steps used = 21, number of rules used = 10, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.526, Rules used = {5930, 5916, 5980, 5910, 5984, 5918, 5948, 6058, 6610, 6062} \[ -\frac{3 \text{PolyLog}\left (3,1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{3 \text{PolyLog}\left (4,1-\frac{2}{1-a x}\right )}{a^3 c}-\frac{3 \text{PolyLog}\left (5,1-\frac{2}{1-a x}\right )}{2 a^3 c}+\frac{2 \tanh ^{-1}(a x)^3 \text{PolyLog}\left (2,1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{6 \tanh ^{-1}(a x)^2 \text{PolyLog}\left (2,1-\frac{2}{1-a x}\right )}{a^3 c}-\frac{3 \tanh ^{-1}(a x)^2 \text{PolyLog}\left (3,1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{6 \tanh ^{-1}(a x) \text{PolyLog}\left (2,1-\frac{2}{1-a x}\right )}{a^3 c}-\frac{6 \tanh ^{-1}(a x) \text{PolyLog}\left (3,1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{3 \tanh ^{-1}(a x) \text{PolyLog}\left (4,1-\frac{2}{1-a x}\right )}{a^3 c}-\frac{x \tanh ^{-1}(a x)^4}{a^2 c}-\frac{\tanh ^{-1}(a x)^4}{2 a^3 c}-\frac{2 x \tanh ^{-1}(a x)^3}{a^2 c}-\frac{2 \tanh ^{-1}(a x)^3}{a^3 c}+\frac{\log \left (\frac{2}{1-a x}\right ) \tanh ^{-1}(a x)^4}{a^3 c}+\frac{4 \log \left (\frac{2}{1-a x}\right ) \tanh ^{-1}(a x)^3}{a^3 c}+\frac{6 \log \left (\frac{2}{1-a x}\right ) \tanh ^{-1}(a x)^2}{a^3 c}-\frac{x^2 \tanh ^{-1}(a x)^4}{2 a c} \]
Antiderivative was successfully verified.
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Rule 5930
Rule 5916
Rule 5980
Rule 5910
Rule 5984
Rule 5918
Rule 5948
Rule 6058
Rule 6610
Rule 6062
Rubi steps
\begin{align*} \int \frac{x^2 \tanh ^{-1}(a x)^4}{c-a c x} \, dx &=\frac{\int \frac{x \tanh ^{-1}(a x)^4}{c-a c x} \, dx}{a}-\frac{\int x \tanh ^{-1}(a x)^4 \, dx}{a c}\\ &=-\frac{x^2 \tanh ^{-1}(a x)^4}{2 a c}+\frac{\int \frac{\tanh ^{-1}(a x)^4}{c-a c x} \, dx}{a^2}+\frac{2 \int \frac{x^2 \tanh ^{-1}(a x)^3}{1-a^2 x^2} \, dx}{c}-\frac{\int \tanh ^{-1}(a x)^4 \, dx}{a^2 c}\\ &=-\frac{x \tanh ^{-1}(a x)^4}{a^2 c}-\frac{x^2 \tanh ^{-1}(a x)^4}{2 a c}+\frac{\tanh ^{-1}(a x)^4 \log \left (\frac{2}{1-a x}\right )}{a^3 c}-\frac{2 \int \tanh ^{-1}(a x)^3 \, dx}{a^2 c}+\frac{2 \int \frac{\tanh ^{-1}(a x)^3}{1-a^2 x^2} \, dx}{a^2 c}-\frac{4 \int \frac{\tanh ^{-1}(a x)^3 \log \left (\frac{2}{1-a x}\right )}{1-a^2 x^2} \, dx}{a^2 c}+\frac{4 \int \frac{x \tanh ^{-1}(a x)^3}{1-a^2 x^2} \, dx}{a c}\\ &=-\frac{2 x \tanh ^{-1}(a x)^3}{a^2 c}-\frac{\tanh ^{-1}(a x)^4}{2 a^3 c}-\frac{x \tanh ^{-1}(a x)^4}{a^2 c}-\frac{x^2 \tanh ^{-1}(a x)^4}{2 a c}+\frac{\tanh ^{-1}(a x)^4 \log \left (\frac{2}{1-a x}\right )}{a^3 c}+\frac{2 \tanh ^{-1}(a x)^3 \text{Li}_2\left (1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{4 \int \frac{\tanh ^{-1}(a x)^3}{1-a x} \, dx}{a^2 c}-\frac{6 \int \frac{\tanh ^{-1}(a x)^2 \text{Li}_2\left (1-\frac{2}{1-a x}\right )}{1-a^2 x^2} \, dx}{a^2 c}+\frac{6 \int \frac{x \tanh ^{-1}(a x)^2}{1-a^2 x^2} \, dx}{a c}\\ &=-\frac{2 \tanh ^{-1}(a x)^3}{a^3 c}-\frac{2 x \tanh ^{-1}(a x)^3}{a^2 c}-\frac{\tanh ^{-1}(a x)^4}{2 a^3 c}-\frac{x \tanh ^{-1}(a x)^4}{a^2 c}-\frac{x^2 \tanh ^{-1}(a x)^4}{2 a c}+\frac{4 \tanh ^{-1}(a x)^3 \log \left (\frac{2}{1-a x}\right )}{a^3 c}+\frac{\tanh ^{-1}(a x)^4 \log \left (\frac{2}{1-a x}\right )}{a^3 c}+\frac{2 \tanh ^{-1}(a x)^3 \text{Li}_2\left (1-\frac{2}{1-a x}\right )}{a^3 c}-\frac{3 \tanh ^{-1}(a x)^2 \text{Li}_3\left (1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{6 \int \frac{\tanh ^{-1}(a x)^2}{1-a x} \, dx}{a^2 c}+\frac{6 \int \frac{\tanh ^{-1}(a x) \text{Li}_3\left (1-\frac{2}{1-a x}\right )}{1-a^2 x^2} \, dx}{a^2 c}-\frac{12 \int \frac{\tanh ^{-1}(a x)^2 \log \left (\frac{2}{1-a x}\right )}{1-a^2 x^2} \, dx}{a^2 c}\\ &=-\frac{2 \tanh ^{-1}(a x)^3}{a^3 c}-\frac{2 x \tanh ^{-1}(a x)^3}{a^2 c}-\frac{\tanh ^{-1}(a x)^4}{2 a^3 c}-\frac{x \tanh ^{-1}(a x)^4}{a^2 c}-\frac{x^2 \tanh ^{-1}(a x)^4}{2 a c}+\frac{6 \tanh ^{-1}(a x)^2 \log \left (\frac{2}{1-a x}\right )}{a^3 c}+\frac{4 \tanh ^{-1}(a x)^3 \log \left (\frac{2}{1-a x}\right )}{a^3 c}+\frac{\tanh ^{-1}(a x)^4 \log \left (\frac{2}{1-a x}\right )}{a^3 c}+\frac{6 \tanh ^{-1}(a x)^2 \text{Li}_2\left (1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{2 \tanh ^{-1}(a x)^3 \text{Li}_2\left (1-\frac{2}{1-a x}\right )}{a^3 c}-\frac{3 \tanh ^{-1}(a x)^2 \text{Li}_3\left (1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{3 \tanh ^{-1}(a x) \text{Li}_4\left (1-\frac{2}{1-a x}\right )}{a^3 c}-\frac{3 \int \frac{\text{Li}_4\left (1-\frac{2}{1-a x}\right )}{1-a^2 x^2} \, dx}{a^2 c}-\frac{12 \int \frac{\tanh ^{-1}(a x) \log \left (\frac{2}{1-a x}\right )}{1-a^2 x^2} \, dx}{a^2 c}-\frac{12 \int \frac{\tanh ^{-1}(a x) \text{Li}_2\left (1-\frac{2}{1-a x}\right )}{1-a^2 x^2} \, dx}{a^2 c}\\ &=-\frac{2 \tanh ^{-1}(a x)^3}{a^3 c}-\frac{2 x \tanh ^{-1}(a x)^3}{a^2 c}-\frac{\tanh ^{-1}(a x)^4}{2 a^3 c}-\frac{x \tanh ^{-1}(a x)^4}{a^2 c}-\frac{x^2 \tanh ^{-1}(a x)^4}{2 a c}+\frac{6 \tanh ^{-1}(a x)^2 \log \left (\frac{2}{1-a x}\right )}{a^3 c}+\frac{4 \tanh ^{-1}(a x)^3 \log \left (\frac{2}{1-a x}\right )}{a^3 c}+\frac{\tanh ^{-1}(a x)^4 \log \left (\frac{2}{1-a x}\right )}{a^3 c}+\frac{6 \tanh ^{-1}(a x) \text{Li}_2\left (1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{6 \tanh ^{-1}(a x)^2 \text{Li}_2\left (1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{2 \tanh ^{-1}(a x)^3 \text{Li}_2\left (1-\frac{2}{1-a x}\right )}{a^3 c}-\frac{6 \tanh ^{-1}(a x) \text{Li}_3\left (1-\frac{2}{1-a x}\right )}{a^3 c}-\frac{3 \tanh ^{-1}(a x)^2 \text{Li}_3\left (1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{3 \tanh ^{-1}(a x) \text{Li}_4\left (1-\frac{2}{1-a x}\right )}{a^3 c}-\frac{3 \text{Li}_5\left (1-\frac{2}{1-a x}\right )}{2 a^3 c}-\frac{6 \int \frac{\text{Li}_2\left (1-\frac{2}{1-a x}\right )}{1-a^2 x^2} \, dx}{a^2 c}+\frac{6 \int \frac{\text{Li}_3\left (1-\frac{2}{1-a x}\right )}{1-a^2 x^2} \, dx}{a^2 c}\\ &=-\frac{2 \tanh ^{-1}(a x)^3}{a^3 c}-\frac{2 x \tanh ^{-1}(a x)^3}{a^2 c}-\frac{\tanh ^{-1}(a x)^4}{2 a^3 c}-\frac{x \tanh ^{-1}(a x)^4}{a^2 c}-\frac{x^2 \tanh ^{-1}(a x)^4}{2 a c}+\frac{6 \tanh ^{-1}(a x)^2 \log \left (\frac{2}{1-a x}\right )}{a^3 c}+\frac{4 \tanh ^{-1}(a x)^3 \log \left (\frac{2}{1-a x}\right )}{a^3 c}+\frac{\tanh ^{-1}(a x)^4 \log \left (\frac{2}{1-a x}\right )}{a^3 c}+\frac{6 \tanh ^{-1}(a x) \text{Li}_2\left (1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{6 \tanh ^{-1}(a x)^2 \text{Li}_2\left (1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{2 \tanh ^{-1}(a x)^3 \text{Li}_2\left (1-\frac{2}{1-a x}\right )}{a^3 c}-\frac{3 \text{Li}_3\left (1-\frac{2}{1-a x}\right )}{a^3 c}-\frac{6 \tanh ^{-1}(a x) \text{Li}_3\left (1-\frac{2}{1-a x}\right )}{a^3 c}-\frac{3 \tanh ^{-1}(a x)^2 \text{Li}_3\left (1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{3 \text{Li}_4\left (1-\frac{2}{1-a x}\right )}{a^3 c}+\frac{3 \tanh ^{-1}(a x) \text{Li}_4\left (1-\frac{2}{1-a x}\right )}{a^3 c}-\frac{3 \text{Li}_5\left (1-\frac{2}{1-a x}\right )}{2 a^3 c}\\ \end{align*}
Mathematica [A] time = 0.406843, size = 233, normalized size = 0.61 \[ -\frac{2 \left (\tanh ^{-1}(a x)^2+3 \tanh ^{-1}(a x)+3\right ) \tanh ^{-1}(a x) \text{PolyLog}\left (2,-e^{-2 \tanh ^{-1}(a x)}\right )+3 \tanh ^{-1}(a x) \text{PolyLog}\left (4,-e^{-2 \tanh ^{-1}(a x)}\right )+3 \left (\tanh ^{-1}(a x)+1\right )^2 \text{PolyLog}\left (3,-e^{-2 \tanh ^{-1}(a x)}\right )+3 \text{PolyLog}\left (4,-e^{-2 \tanh ^{-1}(a x)}\right )+\frac{3}{2} \text{PolyLog}\left (5,-e^{-2 \tanh ^{-1}(a x)}\right )-\frac{1}{2} \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^4-\frac{2}{5} \tanh ^{-1}(a x)^5+a x \tanh ^{-1}(a x)^4-\tanh ^{-1}(a x)^4+2 a x \tanh ^{-1}(a x)^3-2 \tanh ^{-1}(a x)^3-\tanh ^{-1}(a x)^4 \log \left (e^{-2 \tanh ^{-1}(a x)}+1\right )-4 \tanh ^{-1}(a x)^3 \log \left (e^{-2 \tanh ^{-1}(a x)}+1\right )-6 \tanh ^{-1}(a x)^2 \log \left (e^{-2 \tanh ^{-1}(a x)}+1\right )}{a^3 c} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.571, size = 496, normalized size = 1.3 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{4 \, \log \left (-a x + 1\right )^{5} + 5 \,{\left (2 \, \log \left (-a x + 1\right )^{4} - 4 \, \log \left (-a x + 1\right )^{3} + 6 \, \log \left (-a x + 1\right )^{2} - 6 \, \log \left (-a x + 1\right ) + 3\right )}{\left (a x - 1\right )}^{2} + 40 \,{\left (\log \left (-a x + 1\right )^{4} - 4 \, \log \left (-a x + 1\right )^{3} + 12 \, \log \left (-a x + 1\right )^{2} - 24 \, \log \left (-a x + 1\right ) + 24\right )}{\left (a x - 1\right )}}{320 \, a^{3} c} + \frac{1}{16} \, \int -\frac{x^{2} \log \left (a x + 1\right )^{4} - 4 \, x^{2} \log \left (a x + 1\right )^{3} \log \left (-a x + 1\right ) + 6 \, x^{2} \log \left (a x + 1\right )^{2} \log \left (-a x + 1\right )^{2} - 4 \, x^{2} \log \left (a x + 1\right ) \log \left (-a x + 1\right )^{3}}{a c x - c}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{x^{2} \operatorname{artanh}\left (a x\right )^{4}}{a c x - c}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} - \frac{\int \frac{x^{2} \operatorname{atanh}^{4}{\left (a x \right )}}{a x - 1}\, dx}{c} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int -\frac{x^{2} \operatorname{artanh}\left (a x\right )^{4}}{a c x - c}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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